Math, asked by siddharthjagtap42, 8 months ago

[sec theta + tan theta}(sec theta-tan theta)​

Answers

Answered by mrudhula23
1

Step-by-step explanation:

(secthetha+tanthetha)(secthetha-thanthetha)

(sec^2thetha-tan^2thetha)(a+b)(a-b)=a^2-b^2

sec^2thetha-tan^2thetha=1

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