Sec(thita)=5/4, cosec(fy)=13/12 find sec(thita+fy)
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Answered by
1
Step-by-step explanation:
sec(theta+phi)=1/cos(theta+phi)
=1/cos(theta)cos(phi)-sin(theta)sin(phi)
sec(theta)=5/4
cos(theta)=4/5
sin(theta)=3/5
cosec(phi)=1/sin(phi)=13/12
sin(phi)=12/13
cos(phi)=5/13
cos(theta)*cos(phi)=4/5*5/13=4/13
sin(theta)*sin(phi)=3/5*12/13=36/65
answer:4/13-36/65=20-36/65=-16/65
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Answered by
0
Answer:
this
Step-by-step explanation:
is right I thank you for giving the answer
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