Question

Sec(thita)=5/4, cosec(fy)=13/12 find sec(thita+fy)

Answer 1

Step-by-step explanation:

sec(theta+phi)=1/cos(theta+phi)

=1/cos(theta)cos(phi)-sin(theta)sin(phi)

sec(theta)=5/4

cos(theta)=4/5

sin(theta)=3/5

cosec(phi)=1/sin(phi)=13/12

sin(phi)=12/13

cos(phi)=5/13

cos(theta)*cos(phi)=4/5*5/13=4/13

sin(theta)*sin(phi)=3/5*12/13=36/65

answer:4/13-36/65=20-36/65=-16/65

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Answer 2

Answer:

this

Step-by-step explanation:

is right I thank you for giving the answer