Sec thita + tan thita =2 then let us determine the value of sec thita - tan thita
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Given, secβ + tanβ = 2. (thita =β)
Multiplying and dividing this by
secβ - tanβ we get
[sec²(β) - tan²(β)]/(secβ - tanβ) = 2
=> 2(secβ - tanβ) = 1
=> secβ - tanβ = 1/2
Multiplying and dividing this by
secβ - tanβ we get
[sec²(β) - tan²(β)]/(secβ - tanβ) = 2
=> 2(secβ - tanβ) = 1
=> secβ - tanβ = 1/2
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