sec x-1/sec x+1=1-cos x/1+cos x
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Answered by
26
Hi ,
LHS = ( secx - 1 )/( sec x + 1 )
= [ 1/cosx - 1 ]/[ 1/cosx + 1 ]
[ since sec x = 1/cos x ]
= [ (1 - cos x )/cos x ]/[ ( 1 + cosx )/cosx ]
= ( 1 - cosx )/ ( 1 + cos x )
= RHS
I hope this helps you.
: )
LHS = ( secx - 1 )/( sec x + 1 )
= [ 1/cosx - 1 ]/[ 1/cosx + 1 ]
[ since sec x = 1/cos x ]
= [ (1 - cos x )/cos x ]/[ ( 1 + cosx )/cosx ]
= ( 1 - cosx )/ ( 1 + cos x )
= RHS
I hope this helps you.
: )
Answered by
1
Answer:
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