sec x=13/5 x in fourth quadrant then sinx+cosx
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Class 11
>>Maths
>>Trigonometric Functions
>>Trigonometric Functions
>>Find the value of other five trigonometr
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Find the value of other five trigonometric ratios:
secx=
5
13
, x lies in fourth quadrant.
Medium
Solution
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secx=
5
13
⇒cosx=
secx
1
=
13
5
Now ∵sin
2
x+cos
2
x=1
⟹sin
2
x=1−cos
2
x=1−
169
25
=
169
144
⟹sinx=±
13
12
Since x lies in fourth quadrant, the value of sinx will be negative.
∴sinx=−
13
12
cscx=
sinx
1
=−
12
13
tanx=
cosx
sinx
=
(
13
5
)
(−
13
12
)
=−
5
12
cotx=
tanx
1
=−
12
5
Step-by-step explanation:
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