Math, asked by vivekbhardwaj5041, 2 months ago

sec x=13/5 x in fourth quadrant then sinx+cosx

Answers

Answered by ombparmar1610
0

Answer:

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Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Functions

>>Find the value of other five trigonometr

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Find the value of other five trigonometric ratios:

secx=

5

13

, x lies in fourth quadrant.

Medium

Solution

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secx=

5

13

⇒cosx=

secx

1

=

13

5

Now ∵sin

2

x+cos

2

x=1

⟹sin

2

x=1−cos

2

x=1−

169

25

=

169

144

⟹sinx=±

13

12

Since x lies in fourth quadrant, the value of sinx will be negative.

∴sinx=−

13

12

cscx=

sinx

1

=−

12

13

tanx=

cosx

sinx

=

(

13

5

)

(−

13

12

)

=−

5

12

cotx=

tanx

1

=−

12

5

Step-by-step explanation:

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