sec(x) +2=0 solve the problem
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Solve for ? sec(x)+2=0
sec(x)+2=0sec(x)+2=0
Subtract 22 from both sides of the equation.
sec(x)=−2sec(x)=-2
Take the inverse secant of both sides of the equation to extract xx from inside the secant.
x=arcsec(−2)x=arcsec(-2)
The exact value of arcsec(−2)arcsec(-2) is 2π32π3.
x=2π3
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