sec (x -20) = cosec (x -20) ..find the value of x
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0
Step-by-step explanation:
Given,
sec x + cosec x = p
= > \sec(x) = p - \cosec(x) \\ = > \sec(x) - \cosec(x) = p - \csc(x) - \csc(x) \\ = p - 2 \cosec(x).
[csc means cosec only].
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Answered by
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we know that sec theta = cosec( 90 - theta )
sec( x - 20 ) = cosec ( x - 20 )
cosec( 90 - ( x - 20 ) = cosec ( x - 20 )
cosec ( 90 - x + 20 ) = cosec ( x - 20 )
- x + 20 = x - 20
2x = 40
x = 20
hope it helps
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