Question

"sec x + cosec x)(sin x + cos x) = 2 + sec x. cosec x
Cana​

Answer 1

Answer:

hey

Step-by-step explanation:

(sinx+cosx) (secx+cosecx)

(sinx+cosx) (1/cosx+1/sinx)

(sinx+cosx) (sinx+cosx/cosxsinx)

((sinx+cosx)^2/(cosxsinx)

(sin^2x+cos^2x+2sinxcosx/(cosxsinx)

1+2sinxcosx/(cosxsinx)

(1/cosxsinx+2sinxcosx/(cosxsinx)

=secx cosecx+2

2+secxcosecx=RHS

L.H.S=R.H.S

hope it helps

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