sec x + tan x =2 , then the value of sec x is ?
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sec x + tan x = 2. - eq 1
by the trignometric identities
sec square x - tan square x = 1
then,
(sec x + tan x)×( sec x - tan x) = 1
(sec x + tan x) = 1 ÷ (sec x - tan x)
&
(sec x - tan x) = 1 ÷ ( sec x + tan x)
so, by the given equation sec x + tan x = 2
sec x - tan x = 1/2. - eq 2
by adding equation 1&2 we get,
2sec x = 2+1/2
2sec x= 4+1 ÷ 2
2sec x = 5/2
sec x = 5/4
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