sec(x+y)=xy differientate with respect to x
Answers
Answered by
2
heya
______________________________
Sec( x + y ) { 1 + dy/dx } = y + x dy/dx
=>
dy/dx=
{ y - Sec ( x + y ) }
____________
{ Sec ( x + y ) - x }
______________________________
Sec( x + y ) { 1 + dy/dx } = y + x dy/dx
=>
dy/dx=
{ y - Sec ( x + y ) }
____________
{ Sec ( x + y ) - x }
Similar questions