Question

sec°+tan°=5 then sec°-tan°=​

Answer 1

Step-by-step explanation:

secθ−tanθ=0−(i)

we know that sec

2

θ−tan

2

θ=1

secθ+tanθ=

secθ−tanθ

1

=

5

1

−(ii)

Adding (i) & (ii) gives

2secθ=5+

5

1

2secθ=

5

26

secθ=

5

13

cosθ=

13

5

θ=cos

−1

(

13

5

)

Answer 2

Answer:

1/5

Step-by-step explanation:

I already updated answer to this question

so check there