Question

sec16 cosec74-cot74 tan 16

Answer 1

See the attach file for ans

Answer 2

Answer:

sec16 cosec74-cot74 tan 16 = 1

Step-by-step explanation:

Recall the formulas

cosec(90-A) =  sec A

cot (90 - A) =  TanA

sec²A - tan²A = 1

We know,

sec16 cosec74-cot74 tan 16

=sec16cocec(90-16) - cot(90-16)tan16

=sec16sec16 -tan 16 tan 16

= sec² 16 -  tan² 16

= 1 (∵sec² 16 -  tan² 16 = 1)

∴ sec16 cosec74-cot74 tan 16 = 1

#SPJ3