Question

(sec²∅-1)cot²∅=1
$sec$
​

Answer 1

(sec² θ−1)cot²θ=1

L.H.S

=(sec²θ−1)×cot²θ

=(tan² θ)×cot²θ

$= \frac{1}{cot² θ}×cot²θ$

=1

=R.H.S

Hence proved ✓

Answer 2

Answer:

Hope it helps you mate :)