Math, asked by Limon3189, 1 year ago

(Sec2 37°-cot2 53°)tan 21°tan69°-sin 51°cos39°-cos51°sin39°

Answers

Answered by InnocentBachiNo1
4
(sec²37°- cot²53°)tan21°tan69°- sin51°cos39° -cos51°sin39°
→[sec²(90°-53°)-cot²53°]tan(90°- 69°)tan69° -sin51°cos(90°- 51°)- cos51°sin(90°- 51°)
→(cosec²53°- cot²53°)cot69°tan69°- sin51°sin51° -cos51°cos51°
→(1) 1- (sin²51°+ cos²51°)
→1- 1
→0
Similar questions