Question

Sec2 60-tan2 60 / sin 2
30+cos230

Answer 1

Answer

Hope this helps you!!

Answer 2

$\frac{\sec^2 60-\tan^2 60}{\sin^2 30+\cos^2 30}=1$

Step-by-step explanation:

Given : Expression $\frac{\sec^2 60-\tan^2 60}{\sin^2 30+\cos^2 30}$

To find : Solve the expression ?

Solution :

Expression $\frac{\sec^2 60-\tan^2 60}{\sin^2 30+\cos^2 30}$

Using trigonometric values,

$\sin 30=\frac{1}{2}$

$\cos 30=\frac{\sqrt3}{2}$

$\sec 60=2$

$\tan 60=\sqrt3$

Substitute the values,

$=\frac{(2)^2-(\sqrt3)^2}{(\frac{1}{2})^2+(\frac{\sqrt3}{2})^2}$

$=\frac{4-3}{\frac{1}{4}+\frac{3}{4}}$

$=\frac{1}{\frac{4}{4}}$

$=\frac{1}{1}$

$=1$

Therefore, $\frac{\sec^2 60-\tan^2 60}{\sin^2 30+\cos^2 30}=1$

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