Question

sec²(90° – Theta) + tan²(90° – Theta)
= cosec²0 + cot²
Prove​

Answer 1

Answer:

Step-by-step explanation:

Sec(90-Φ)=cosecΦ......................(1)

sec$^{2}(90-$Φ= Cosec$^{2}$Φ

Tan(90-Φ)= CotΦ...........................(2)

Tan$^{2}$(90-Φ) =cot$^{2}$Φ

(1)+(2)

==   sec$^{2}(90-$Φ+Tan$^{2}$(90-Φ) =Cosec$^{2}$Φ +cot$^{2}$Φ

Answer 2

Answer:

to prove:

sec²(90°–Φ)+tan²(90°–Φ)

sec(90–Φ)=cosec Φ

tan (90–Φ)=cotΦ

so.... by using the identities.

putting the values of these. and, then we get

=cosec²Φ+cot²Φ

proved...

Step-by-step explanation:

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