sec²( arc tan 2 ) + cosec ²( arc cot 3 ) = ? pls ans this question
Answers
Answered by
2
Answer:
15
Step-by-step explanation:
Given,
sec²(tan⁻¹{2}) + cosec²(cot⁻¹{3})
[∴ sec²∅ = 1 + tan²∅, cosec² = 1 + cot²∅]
=> 1 + tan²(tan⁻¹ 2) + 1 + cot²(cot⁻¹ 3)
[∴ tan(tan⁻¹ x) = x, cot(cot⁻¹ x) = x]
=> 1 + 2² + 1 + 3²
=> 1 + 4 + 1 + 9
=> 15
Hope it helps!
Answered by
0
Answer:
15
plz mark as brainlist answer...
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