Question

sec2 @÷tan2 @ + cosec2 @÷cot2 @= sec2@× cosec2 @​

Answer 1

hope it would help you.

Answer 2

Answer:

Step-by-step explanation:

sec2 @÷tan2 @ + cosec2 @÷cot2 @= sec2@× cosec2 @

LHS,

⇒1/cos2@÷sin2@/cos2@+1/sin2@÷cos2@/sin2@

cancelling cos2@ and sin2@

⇒1/sin2@+1/cos2@

Take LCM,

⇒(sin2@+cos2@)÷sin2@×cos2@

⇒1÷(sin2@×cos2@)

⇒sec2@× cosec2 @

therefore,

LHS=RHS