Question

sec²Φ+cosec²Φ=sec²Φ×cosec²Φ​

Answer 1

Answer:

proved below step by step

Step-by-step explanation:

sec²Ф+cosec²Ф=sec²Ф×cosec²Ф

L.H.S=sec²Ф+cosec²Ф

        =(1/cos) ²Ф+(1/sin)²Ф

        =(1/cos²Ф)+(1/sin²Ф)

        =(sin²Ф+cos²Ф)/(sin²Ф cos²Ф)

        =1/sin²Ф cos²Ф

        =(1/sin²Ф)×(1/cos²Ф)

        =cosec²Ф × sec²Ф =R.H.S.