Question

sec²+cosec²= sec²×cosec²​

Answer 1

HEYA MATE ,

HERE IS YOUR ANSWER,

Cosec

2

A+Sec

2

A=

Sin

2

A

1

+

Cos

2

A

1

=\frac{ Cos^{2}A + Sin^{2}A}{Cos^{2}ASin^{2}A}

Cos

2

ASin

2

A

Cos

2

A+Sin

2

A

=\frac{1}{Cos^{2}A.Sin^{2} }

Cos

2

A.Sin

2

1

(where Sin^{2}A+Cos^{2}A = 1)(whereSin

2

A+Cos

2

A=1)

=\frac{1}{Cos^{2}A } . \frac{1}{Sin^{2}A }

Cos

2

A

1

.

Sin

2

A

1

=Sec^{2}A.Cosec^{2}ASec

2

A.Cosec

2

A

HOPE IT HELPS YOU.

IF IT HELPS YOU PLZ BE MY FOLLOWER