Math, asked by vishalch9699, 11 months ago

sec²+cosec²= sec²×cosec²​

Answers

Answered by khushi4436
10
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Answered by anildeshmukh
4

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Answer:

Step-by-step explanation:

Sec²+cosec²= LHS

sec²×cosec²​=RHS

1/cos^2+1/sin^2........... sec2=1/cos^2

Cosec=1/sin^2

Sin^2+cos^2/cos^2×sin^2

....... by doing base same

Sin2+cos2=1.....identity

____ 1/cos^2×sin^2

1/cos^2×1 sin^2

1/Cos2=sec2..... and 1/sin2= cosec 2

Sec^2×cosec^2...

LHS=RHS

HENCE PROVED

Sec²+cosec²= sec²×cosec²


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