(sec² Q-1)(1-cosec²theta )= -1
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Step-by-step explanation:
Here let Q be equals to Thetha.
Remember THESE FORMULA : [1 + tan²Q = sec²Q] and [ 1 + cot²Q = cosec²Q]
(sec²Q - 1) (1 - cosec²Q) = -1
Now LHS = (sec²Q - 1) (1 - cosec²Q) -------------(1)
(tan²Q) (-cot²Q)
(tan²Q × -1 / tan²Q)
Now tan²Q will cancel out and we will get ,
-1
Hence we get LHS = -1
AND LHS = RHS
HENCE PROVED
PLEASE MARK IT BRAINLIEST.
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