Sec² theta = 1 + Cot²theta
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1
Answer:
θ−1)cot
2
θ=1
Medium
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(sec
2
θ−1)cot
2
θ=1
L.H.S
=(sec
2
θ−1)×cot
2
θ
=(tan
2
θ)×cot
2
θ
=
cot
2
θ
1
×cot
2
θ
=1
=R.H.S
Hence proved.
Step-by-step explanation:
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