sec² theta + cosec² theta = sec² theta cosec² theta
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Answered by
13
Step-by-step explanation:
LHS=sec^2A + cosec^2A
=(1/cos^2A) + (1/sin^2A)
=sin^2A+cos^2A/cos^2A*sin^2A
(by taking LCM)
=1/cos^2A*sin^2A
=1/cos^2A*1/sin^2A
(by taking 1 on both sides)
=sec^2Acosec^2A
(since, 1/cos=sec and
1/sin=cosecA)
... Hence the proof...
Answered by
19
Answer:
The proof has been attached below..
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