Math, asked by renabukkawar, 5 months ago

Sec2 theta + cosec2 theta = sec2 theta × cosec2 theta ​

Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

sec

2

θ

+

cos

e

c

2

θ

 can be written as

1

cos

2

θ

+

1

sin

2

θ

Taking lcm

sin

2

θ

+

cos

2

θ

sin

2

θ

cos

2

θ

recall

sin

2

A

+

cos

2

A

=

1

1

sin

2

θ

cos

2

θ

1

sin

2

θ

1

cos

2

θ

cos

e

c

2

θ

×

sec

2

θ

Hence proved

Answered by sanidhya7672
0

Answer:

2354e5r4 is the answer of this qustion

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