Math, asked by trushnamayeemajhi20, 4 months ago

sec2180° + tan 150°
cosec90° - cotl200 = 2 - 13
(iii)
sec²180° + tan 45º
cosec 90° - cot120°
=3-√3

Answers

Answered by dimplesokhal123

0

Answer:

please write clearly.... .....

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