Math, asked by ramakrishna59, 1 year ago

(sec²38° - 1)(cos ec² 38° - 1) =​

Answers

Answered by sugha58
1

Step-by-step explanation:

given,

(sec^2 38°-1)(cosec^2 38°-1)

1. sec^2 x-1=tan^2 x

2. cosec^2 x-1=cot^2 x

substitute 1&2 in given eq,

=(tan^2 38°)(cot^2 38°)

=(tan^2 38°)(1/tan^2 38°)

=1

The value of (sec^2 38°-1)

(cosec^2 38°-1) = 1

Similar questions