Math, asked by rajashreedeb4, 6 months ago

Sec²60⁰-cot²30⁰-2tan30⁰cosec60⁰÷1+tan²30⁰

Answers

Answered by Flaunt
57

\huge\tt{\bold{\underline{\underline{Question᎓}}}}Sec²60⁰-cot²30⁰-2tan30⁰cosec60⁰÷1+tan²30⁰

\huge\tt{\bold{\underline{\underline{Answer᎓}}}}

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Before solving take a look into trigonometric table :

  =  > Sec²60⁰-cot²30⁰-2tan30⁰cosec60⁰÷1+tan²30⁰

 =  >  {(2)}^{2}  -  {( \sqrt{3} )}^{2}  - 2( { \sqrt{3}) }^{2} (2) \div 1 +  {( \sqrt{3} )}^{2}

 =  > 4 - 3 - 2(3)(2) \div 1 + 3

 =  > 1 - 12 \div 4

1 -  \frac{12}{4}  = 1 - 3 =  - 2

 =  - 2

-2 is your answer

\bold{\underline{\underline{Note:}}} Not defined means 0 comes as denominator so we called it Not Defined (ND)

There are four cases of Not Defined

e.g.->Cosec0°,Cot0°,Tan90° & Sec90°

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