Question

sec260° – tan60°
sin230° + cos²30°​

Answer 1

Answer:

${sec}^{2}{60}^{o} - \: tan {60}^{o} \\ = {2}^{2} - \sqrt{3} \\ = 4 - \sqrt{3}$

${sin}^{2} {30}^{o} + {cos}^{2} {30}^{o} \\ = (\frac{1}{2})^{2} + ( \frac{ \sqrt{3} }{2} )^{2} \\ = \frac{1}{4} + \frac{3}{4} \\ = \frac{4}{4} \\ = 1$

hope it helps dear...❤✌

Answer 2

HERE IS ANSWER TO THE QUESTION❣❣❇❇✌✌