Question

sec29 degree by cosec 61 degree + 2cot8 degree cot 17 degree cot 45 degree cot 73 degree cot 82 degree -3 ( sin square 38 dregee +sin square 52 dregee).​

Answer 1

The answer is zero(0)

Sec(90-theta) =cosectheta;

Cot(90-theta) =tantheta;

Sin(90-theta) =costheta;

Sin²theta+cos²theta=1

Sec29°=sec(90-61) =cosec61

Cot8=cot(90-82) =tan82

Cot17=cot (90-73) =tan73

Cot45°=1

Sin38=sin(90-53) =cos53

So in question,

=1+2(1) -3(1)

=0