(Sec²A-1)(1-cosec²A)=1
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Answered by
17
HEY mate here is your answer.
hope it helps you.
^_^
hope it helps you.
^_^
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Answered by
12
Hey there !
Solution :
We know the identities that,
Sin² A + Cos² A = 1
Sec² A - Tan² A = 1
Cosec² A - Cot² A = 1
So, According to the question,
( Sec² A - 1 ) ( Cosec² A - 1 ) = 1
LHS :
According to identity,
Sec² A - Tan² A = 1
=> Sec² A - 1 = Tan² A
Similarly,
Cosec² A - Cot² A = 1
=> Cosec² A - 1 = Cot² A.
So substituting them in place of the question we get,
( Tan² A ) ( Cot² A )
We know that, Cot² A = 1 / Tan² A
Hence substituting Cot² A we get
Tan² A * 1 / Tan² A
=> Tan² A / Tan² A
=> 1
RHS :
=> 1
Hence LHS = RHS.
Hence proved.
Hope it helped :-)
Solution :
We know the identities that,
Sin² A + Cos² A = 1
Sec² A - Tan² A = 1
Cosec² A - Cot² A = 1
So, According to the question,
( Sec² A - 1 ) ( Cosec² A - 1 ) = 1
LHS :
According to identity,
Sec² A - Tan² A = 1
=> Sec² A - 1 = Tan² A
Similarly,
Cosec² A - Cot² A = 1
=> Cosec² A - 1 = Cot² A.
So substituting them in place of the question we get,
( Tan² A ) ( Cot² A )
We know that, Cot² A = 1 / Tan² A
Hence substituting Cot² A we get
Tan² A * 1 / Tan² A
=> Tan² A / Tan² A
=> 1
RHS :
=> 1
Hence LHS = RHS.
Hence proved.
Hope it helped :-)
DavidOtunga:
Great job :)
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