Question

Sec²A.cos²A-(tan²A+cot²A)=

Answer 1

Answer:

Step-by-step explanation:

Sec²a.cos²a-(tan²a+cot²a)

= cos²a/cos²a -(sin²a/cos²a + cos²a/sin²a)

= 1-(sin^4a +cos^4a)/sin²a cos²a

using formula

a²+b² = (a+b)²-2ab

= 1-[(sin²a+cos²a)²-2sin²acos²a]/sin²acos²a

=1-(1/sin²acos²a. )+2

= 3- 1/sin²acos²a