Question

sec²A + cose c²A = sec²A x cosec²A
To prove the above ?

Answer 1

I hope this answer is helpful and u understand the handwriting

Answer 2

★ Question:

to prove :

sec²x + cosec ²x = sec²x cosec²x

★ Answer :

LHS

= sec²A + cose c²A

$= \frac{1}{ \cos {}^{2} (x) } \times + \frac{1}{ \sin {}^{2} (x) }$

$= \frac{ \sin {}^{2} (x) + \cos {}^{2} (x) }{ \sin {}^{2} (x) \cos {}^{2} (x) }$

$= \frac{1}{ \sin {}^{2} (x) \cos {}^{2} (x) }$

$= \sec {}^{2} (x) \times \csc {}^{2} (x)$

= RHS

hence proved