Sec²A
cosec
A (tan AtcoTZA)
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Answer:
Explanation: We know that:
sec²x = 1 + tan²x
And
cosec²x = 1 + cot²x
And
tan x .cot x = 1
Solution:-
Taking LHS..
= √(sec²A + cosec²A)
= √ { (1 + tan²A) + ( 1 + cot²A) }
= √ ( tan²A + cot²A + 2)
= √ ( tan²A + cot²A + 2 tan A .cot A )
Using
(a² + b² +2ab) = (a + b)²
= √(tan A + cot A)²
= tan A + cot A = RHS
Hence;
Proved √ (sec²A+cosec²A) = tan A + cot A
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