Math, asked by Rutvi27, 1 year ago

sec2A + cosec2A = sec2A * cosec2A

Answers

Answered by mysticd
157
lhs = sec²A +cosec²A

= 1/cos²A + 1/sin²A

= (sin²A +cos²A)/(cos²Asin²A)
=1/(cos²Asin²A) {since sin²A +cos²A =1}
= 1/cos²A *1/sin²A
= sec²A cosec²A
=RHS

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Answered by debarpan20
20

Answer:

here is the answer

Step-by-step explanation:

  1. hence proved hope it helped you
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