Math, asked by Rutuja9623, 1 year ago

sec2A + cosec2A = sec2A.cosec2A

Answers

Answered by lucky1498
10
Lhs = sec²A +cosec²A

= 1/cos²A + 1/sin²A

= (sin²A +cos²A)/(cos²Asin²A)
=1/(cos²Asin²A) {since sin²A +cos²A =1}
= 1/cos²A *1/sin²A
= sec²A cosec²A
=RHS
Is this ur ans

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