Math, asked by TejasTarle, 1 year ago

sec2a+cosec2a=sec2axcosec2a

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Answered by ravi34287

0

LHS = sec2A + cosec2A =1cos2A + 1 sin2A =sin2A + cos2Acos2A . sin2A =1cos2A . sin2A =1 cos2A × 1sin2A =sec2A × cosec2A =RHS

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