sec2a+cosec2a=sec2axcosec2a
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LHS = sec²A +cosec²A
= 1/cos²A + 1/sin²A
= (sin²A +cos²A)/(cos²Asin²A)
=1/(cos²Asin²A) {since sin²A +cos²A =1}
= 1/cos²A *1/sin²A
= sec²A cosec²A = RHS PROVED
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