Math, asked by FayzanOP, 11 months ago

sec²a(I+sin a) (1-sin a) =k, find k.​

Answers

Answered by rachitsharma2
0

Answer:

k=1

Step-by-step explanation:

sec²a(1+sin a)(1-sin a)=k

L.H.S

sec²a(1-sin²a). ((a+b)(a-b)=a²-b²)

sec²a×cos²a. (cos×sec=1)

=1=k

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