sec²a(I+sin a) (1-sin a) =k, find k.
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Answer:
k=1
Step-by-step explanation:
sec²a(1+sin a)(1-sin a)=k
L.H.S
sec²a(1-sin²a). ((a+b)(a-b)=a²-b²)
sec²a×cos²a. (cos×sec=1)
=1=k
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