Question

Sec²A - tan²A is equal tot​

Answer 1

Answer:

1

Step-by-step explanation:

${ \sec}^{2}x = \tan^{2} x + 1 \\ therefore \\ \\ \sec^{2} x - \tan^{2}x = \tan^{2} x + 1 - \tan^{2} \\ = 1$

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