Question

sec2theta +cosec2theta= sec2theta ×cosec2theta. plz answer fast .wrong answer will be reported

Answer 1

this is the answer of your question

Answer 2

Hi Friend ✋✋✋

to prove:

Sec²∅ + Cosec²∅ = sec²∅ × cosec²∅

Proof :

LHS :

$\frac{1}{ {cos}^{2} \alpha } + \frac{1}{ {sin}^{2} \alpha } \\ \\ = \frac{ {sin}^{2} \alpha + {cos}^{2} \alpha }{ {sin}^{2} \alpha \times {cos}^{2} \alpha } \\ \\ by \: using \: trigonometric \: identity \\ \\ = \frac{1}{ {sin}^{2} \alpha \times {cos}^{2} \alpha } \\ \\ = cosec {}^{2} \alpha \times sec {}^{2} \alpha$


Therefore , LHS = RHS .... hence proved