Math, asked by navarasanrs, 11 months ago

√sec²theta+cosec²theta =(tantheta +cottheta)

Answers

Answered by adventholy04

1

Answer:

proof

Step-by-step explanation:

LHS

√sec²theta+cosec²theta

√1/cos²theta+1/sin²theta

on solving it results

1/sintheta×costheta

RHS

sintheta/costheta+costheta/sintheta

on solving it' results

1/sintheta×costheta

hence LHS=RHS

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