√sec²theta+cosec²theta =(tantheta +cottheta)
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Answer:
proof
Step-by-step explanation:
LHS
√sec²theta+cosec²theta
√1/cos²theta+1/sin²theta
on solving it results
1/sintheta×costheta
RHS
sintheta/costheta+costheta/sintheta
on solving it' results
1/sintheta×costheta
hence LHS=RHS
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