Sec2theta (sec2theta-2)+1=tan4theta
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sec²θ(sec²θ-2)+1
=sec⁴θ-2sec²θ+1
=(sec²θ)²-2.sec²θ².1+1²
=(sec²θ-1)²
=(tan²θ+1-1)²
[∵, sec²θ-tan²θ=1]
=(tan²θ)²
=tan⁴θ (Proved)
=sec⁴θ-2sec²θ+1
=(sec²θ)²-2.sec²θ².1+1²
=(sec²θ-1)²
=(tan²θ+1-1)²
[∵, sec²θ-tan²θ=1]
=(tan²θ)²
=tan⁴θ (Proved)
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