Math, asked by thephenominalsk11, 8 months ago

(Sec²thetha - 1)into cot²thetha =1 prove it

Answers

Answered by FehlingSolution
13

( {sec}^{2}  \theta - 1) {cot}^{2}  \theta

 {tan}^{2} \theta . {cot}^{2}  \theta

 {tan}^{2} \theta  \times  \frac{1}{ {tan}^{2}  \theta}

1

predefined results used above

1 +  {tan}^{2}  \theta =  {sec}^{2}  \theta

and

 {cot}^{2}  \theta =  \frac{1}{ {tan}^{2} \theta }

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Answered by pulakmath007
2

Answer:

( Sec² θ- 1 ) × cot² θ

= tan² θ × cot² θ

= tan² θ × ( 1/ tan² θ)

= 1

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