Question

sec²x+tan²x=13/12 then sec⁴x-tan⁴x=?

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Answer 1

Answer:

$\frac{13}{12}$

Step-by-step explanation:

${ \sec}^{4} x - { \tan}^{4} x \\ = {( { \sec}^{2}x) }^{2} - { }{ (\tan ^{2}x) }^{2} = ( { \sec}^{2}x + { \tan }^{2} x)( { \sec}^{2} x - { \tan}^{2} x) = \frac{13}{12} \times 1 \\ = \frac{13}{12}$