Question

sec3 θ + cosec3 θ = (sec θ cosec θ)2(sec θ cosec θ – 1)

Answer 1

Answer:

answer is one if yes then please follow me

Answer 2

1/cos^3 θ + 1/sin^3 θ = [1/(sin θ cos θ)3] [1 – sin θ cos θ]

⇒ (sin^3 θ + cos^3 θ) = 1 – sin θ cos θ

⇒ (sin θ + cos θ) (sin^2 θ + cos^2 θ – sin θ cos θ) = 1 – sin θ cos θ

{1-(sin 2θ)/2} {√2 cos (θ - π /4) -1} = 0

either 1- ((sin 2θ)/2 = 0 ⇒ sin 2θ = 2

⇒No solution as sin–1/2 is meaningless.

or, √2 cos (θ - π/4) – 1 = 0 ⇒ θ – π /4 = 2nπ ± π /4

⇒ θ = 2nπ + π /4 + π /4, where n = 0, ±1, ±2 ………

Hope it helps