Question

sec31° sin59° + cos31° cosec59° = 2 prove it

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Answer 1

Answer:

Step-by-step explanation:L.H.S.

sec 31°×sin59°+cos 31° ×cosec59°

=cosec(90°-31°)×sin59°+sin(90°-31°)×cosec 59°

=cosec59°×sin59°+sin 59°×cosec 59°

•.•sin theta × cosec theta =1

.•. cosec59°×sin59°+sin 59°×cosec 59

=1+1

=2

=R.H.S. proved

hope this will help you.

Answer 2

Answer:

we know that cos = 1/sec

and sin= 1/cosec

31° + 59° = 90° degree ( so the question is right the angles should always add up-to 90 degree)

so proceeding sec 31° = 1/ cos 31°

   while cosec 59°  = 1/sin 59°

1/ cos 31° x sin 59° + cos 31° x 1/sin 59°

sin 59°/cos 31° + cos 31°/sin 59°

sin (90° - 31°)/ cos 31° + cos 31° / sin (90° - 31°)

cos 31°/ cos 31° + cos 31° / cos 31°

1 + 1 = 2

welcome;)