Question

sec4 0 + tan4 0 = 1 + 2 sec² 0 tan² 0


0 is Thelta​

Answer 1

Step-by-step explanation:

sec⁴A+tan⁴A

=(sec²A)²+(tan²A)²

=(sec²A-tan²A)²+2sec²Atan²A

=1+2sec²Atan²A

replacing theta by A