Question

sec4 A-tan4A=1+2tan2A​

Answer 1

Step-by-step explanation:

(sec²A) ²_(tan²A) ²

we know that a²_b²=(a+b)(a_b)

(sec²A+tan²A) (sec²A_tan²A)

we know that sec²A_tan²A=1

(sec²A+tan²A) 1

we know that sec²A=1+tan²A

1+tan²A+tan²A

1+2tan²A

so sec4A_tan4A=1+2tan²A

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