Question

sec4¤=cosec(¤+20),then ¤ is​

Answer 1

Sec4○=cosec(○+20)

Cosec(90-4○)=cosec(○+20)

90-4○=○+20

90-20=○+4○

70=5○

○=14

Answer 2

Answer:

WE KNOW THAT

SEC∅=COSEC(90-∅)

SO SEC4∅=COSEC(∅+20)

∅=4∅

SO

COSEC(90-4∅)=COSEC(∅+20)

COSEC WILL BE CUT DOWN

SO ,90-4∅=∅+20

TAKING NUMBER ONE SIDE AND ∅ ONE SIDE

SO 90-20=∅+4∅

70=5∅,

∅=14 ANS